Base | Representation |
---|---|
bin | 1001001001111011001001… |
… | …01111100010101110001011 |
3 | 2122021121201202122220112012 |
4 | 10210331210233202232023 |
5 | 10114321222141312224 |
6 | 110452334511410135 |
7 | 4145334505443332 |
oct | 444754457425613 |
9 | 78247652586465 |
10 | 20132201900939 |
11 | 6462023144a07 |
12 | 231190982394b |
13 | b305c640421b |
14 | 4d8591d3ad19 |
15 | 24da4118e80e |
hex | 124f64be2b8b |
20132201900939 has 2 divisors, whose sum is σ = 20132201900940. Its totient is φ = 20132201900938.
The previous prime is 20132201900917. The next prime is 20132201900989. The reversal of 20132201900939 is 93900910223102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20132201900939 - 212 = 20132201896843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20132201900896 and 20132201900905.
It is not a weakly prime, because it can be changed into another prime (20132201900989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066100950469 + 10066100950470.
It is an arithmetic number, because the mean of its divisors is an integer number (10066100950470).
Almost surely, 220132201900939 is an apocalyptic number.
20132201900939 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132201900939 is an equidigital number, since it uses as much as digits as its factorization.
20132201900939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 20132201900939 in words is "twenty trillion, one hundred thirty-two billion, two hundred one million, nine hundred thousand, nine hundred thirty-nine".
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