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201322031113 = 728760290159
BaseRepresentation
bin1011101101111110111…
…0100110100000001001
3201020122110220211020201
42323133232212200021
511244301414443423
6232252553452201
720354643013060
oct2733756464011
9636573824221
10201322031113
11784200467a5
1233026411061
1315ca519bbc8
149a5b8d91d7
1553845672ad
hex2edfba6809

201322031113 has 4 divisors (see below), whose sum is σ = 230082321280. Its totient is φ = 172561740948.

The previous prime is 201322031111. The next prime is 201322031159. The reversal of 201322031113 is 311130223102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201322031113 - 21 = 201322031111 is a prime.

It is a super-2 number, since 2×2013220311132 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (201322031111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14380145073 + ... + 14380145086.

It is an arithmetic number, because the mean of its divisors is an integer number (57520580320).

Almost surely, 2201322031113 is an apocalyptic number.

It is an amenable number.

201322031113 is a deficient number, since it is larger than the sum of its proper divisors (28760290167).

201322031113 is an equidigital number, since it uses as much as digits as its factorization.

201322031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28760290166.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 201322031113 its reverse (311130223102), we get a palindrome (512452254215).

The spelling of 201322031113 in words is "two hundred one billion, three hundred twenty-two million, thirty-one thousand, one hundred thirteen".

Divisors: 1 7 28760290159 201322031113