Base | Representation |
---|---|
bin | 1001001001111011001010… |
… | …10010101010001001100001 |
3 | 2122021121202101222121001020 |
4 | 10210331211102222021201 |
5 | 10114321232020401101 |
6 | 110452335441000053 |
7 | 4145334646623402 |
oct | 444754522521141 |
9 | 78247671877036 |
10 | 20132211106401 |
11 | 6462028362129 |
12 | 2311910923029 |
13 | b305c82a8244 |
14 | 4d85932559a9 |
15 | 24da41dac136 |
hex | 124f654aa261 |
20132211106401 has 4 divisors (see below), whose sum is σ = 26842948141872. Its totient is φ = 13421474070932.
The previous prime is 20132211106367. The next prime is 20132211106429. The reversal of 20132211106401 is 10460111223102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20132211106401 - 211 = 20132211104353 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20132211116401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355368517731 + ... + 3355368517736.
It is an arithmetic number, because the mean of its divisors is an integer number (6710737035468).
Almost surely, 220132211106401 is an apocalyptic number.
It is an amenable number.
20132211106401 is a deficient number, since it is larger than the sum of its proper divisors (6710737035471).
20132211106401 is an equidigital number, since it uses as much as digits as its factorization.
20132211106401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6710737035470.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 20132211106401 its reverse (10460111223102), we get a palindrome (30592322329503).
The spelling of 20132211106401 in words is "twenty trillion, one hundred thirty-two billion, two hundred eleven million, one hundred six thousand, four hundred one".
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