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20132311301147 is a prime number
BaseRepresentation
bin1001001001111011010110…
…10000110111110000011011
32122021122000101112000101202
410210331223100313300123
510114321433143114042
6110452353420304415
74145340304356353
oct444755320676033
978248011460352
1020132311301147
116462079976a01
12231193a3a210b
13b30612c89586
144d85a2697b63
1524da4aa9e632
hex124f6b437c1b

20132311301147 has 2 divisors, whose sum is σ = 20132311301148. Its totient is φ = 20132311301146.

The previous prime is 20132311301131. The next prime is 20132311301177. The reversal of 20132311301147 is 74110311323102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20132311301147 - 24 = 20132311301131 is a prime.

It is a super-3 number, since 3×201323113011473 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (20132311301177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066155650573 + 10066155650574.

It is an arithmetic number, because the mean of its divisors is an integer number (10066155650574).

Almost surely, 220132311301147 is an apocalyptic number.

20132311301147 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132311301147 is an equidigital number, since it uses as much as digits as its factorization.

20132311301147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 29.

Adding to 20132311301147 its reverse (74110311323102), we get a palindrome (94242622624249).

The spelling of 20132311301147 in words is "twenty trillion, one hundred thirty-two billion, three hundred eleven million, three hundred one thousand, one hundred forty-seven".