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20132412420313 is a prime number
BaseRepresentation
bin1001001001111011100010…
…10010100111000011011001
32122021122021102210101211001
410210331301102213003121
510114322140034422223
6110452411431505001
74145342643022414
oct444756122470331
978248242711731
1020132412420313
116462120a62266
122311968228161
13b3062ac025bb
144d85b1c9ab7b
1524da548c59ad
hex124f714a70d9

20132412420313 has 2 divisors, whose sum is σ = 20132412420314. Its totient is φ = 20132412420312.

The previous prime is 20132412420259. The next prime is 20132412420331. The reversal of 20132412420313 is 31302421423102.

Together with next prime (20132412420331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18077352552009 + 2055059868304 = 4251747^2 + 1433548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20132412420313 is a prime.

It is not a weakly prime, because it can be changed into another prime (20132412427313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066206210156 + 10066206210157.

It is an arithmetic number, because the mean of its divisors is an integer number (10066206210157).

Almost surely, 220132412420313 is an apocalyptic number.

It is an amenable number.

20132412420313 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132412420313 is an equidigital number, since it uses as much as digits as its factorization.

20132412420313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 20132412420313 its reverse (31302421423102), we get a palindrome (51434833843415).

The spelling of 20132412420313 in words is "twenty trillion, one hundred thirty-two billion, four hundred twelve million, four hundred twenty thousand, three hundred thirteen".