Base | Representation |
---|---|
bin | 10010101111111111… |
… | …011111010001001001 |
3 | 1220222001220020112212 |
4 | 102233333133101021 |
5 | 312212411301004 |
6 | 13125421514505 |
7 | 1311621432353 |
oct | 225777372111 |
9 | 56861806485 |
10 | 20132525129 |
11 | 85a1316122 |
12 | 3a9a412a35 |
13 | 1b8ac98882 |
14 | d8db420d3 |
15 | 7cc6e796e |
hex | 4affdf449 |
20132525129 has 2 divisors, whose sum is σ = 20132525130. Its totient is φ = 20132525128.
The previous prime is 20132525113. The next prime is 20132525143. The reversal of 20132525129 is 92152523102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19723393600 + 409131529 = 140440^2 + 20227^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132525129 - 24 = 20132525113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20132525095 and 20132525104.
It is not a weakly prime, because it can be changed into another prime (20132525429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066262564 + 10066262565.
It is an arithmetic number, because the mean of its divisors is an integer number (10066262565).
Almost surely, 220132525129 is an apocalyptic number.
It is an amenable number.
20132525129 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132525129 is an equidigital number, since it uses as much as digits as its factorization.
20132525129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
The spelling of 20132525129 in words is "twenty billion, one hundred thirty-two million, five hundred twenty-five thousand, one hundred twenty-nine".
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