Base | Representation |
---|---|
bin | 10010110000000001… |
… | …010011001110110001 |
3 | 1220222002210101002212 |
4 | 102300001103032301 |
5 | 312213022000423 |
6 | 13125440021505 |
7 | 1311625451222 |
oct | 226001231661 |
9 | 56862711085 |
10 | 20133000113 |
11 | 85a160aa76 |
12 | 3a9a601895 |
13 | 1b8b103b25 |
14 | d8dc27249 |
15 | 7cc78d578 |
hex | 4b00533b1 |
20133000113 has 16 divisors (see below), whose sum is σ = 21373239936. Its totient is φ = 18924554880.
The previous prime is 20133000109. The next prime is 20133000149. The reversal of 20133000113 is 31100033102.
It is a cyclic number.
It is not a de Polignac number, because 20133000113 - 22 = 20133000109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20133020113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 633245 + ... + 664277.
It is an arithmetic number, because the mean of its divisors is an integer number (1335827496).
Almost surely, 220133000113 is an apocalyptic number.
20133000113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20133000113 is a deficient number, since it is larger than the sum of its proper divisors (1240239823).
20133000113 is a wasteful number, since it uses less digits than its factorization.
20133000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31544.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 20133000113 its reverse (31100033102), we get a palindrome (51233033215).
The spelling of 20133000113 in words is "twenty billion, one hundred thirty-three million, one hundred thirteen", and thus it is an aban number.
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