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2013303310401 = 3671101103467
BaseRepresentation
bin11101010011000010001…
…110101000100001000001
321010110200120101001002010
4131103002032220201001
5230441221121413101
64140522045043133
7265312350530415
oct35230216504101
97113616331063
102013303310401
11706923260899
122862372564a9
13117b13722886
146d631610d45
1537585d942d6
hex1d4c23a8841

2013303310401 has 4 divisors (see below), whose sum is σ = 2684404413872. Its totient is φ = 1342202206932.

The previous prime is 2013303310399. The next prime is 2013303310429. The reversal of 2013303310401 is 1040133033102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2013303310401 - 21 = 2013303310399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013803310401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335550551731 + ... + 335550551736.

It is an arithmetic number, because the mean of its divisors is an integer number (671101103468).

Almost surely, 22013303310401 is an apocalyptic number.

It is an amenable number.

2013303310401 is a deficient number, since it is larger than the sum of its proper divisors (671101103471).

2013303310401 is an equidigital number, since it uses as much as digits as its factorization.

2013303310401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671101103470.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 2013303310401 its reverse (1040133033102), we get a palindrome (3053436343503).

The spelling of 2013303310401 in words is "two trillion, thirteen billion, three hundred three million, three hundred ten thousand, four hundred one".

Divisors: 1 3 671101103467 2013303310401