Base | Representation |
---|---|
bin | 101101110001110000011001… |
… | …011001001110100101011001 |
3 | 222101212002022100221021200221 |
4 | 231301300121121032211121 |
5 | 202342103012112323113 |
6 | 1552110154531400041 |
7 | 60256464423225442 |
oct | 5561603131164531 |
9 | 871762270837627 |
10 | 201331313011033 |
11 | 59172148553157 |
12 | 1a6b7435453021 |
13 | 88455cc7905ca |
14 | 37a06b7b642c9 |
15 | 1842151eed98d |
hex | b71c1964e959 |
201331313011033 has 4 divisors (see below), whose sum is σ = 201331421992960. Its totient is φ = 201331204029108.
The previous prime is 201331313011027. The next prime is 201331313011057. The reversal of 201331313011033 is 330110313133102.
201331313011033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201331313011033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201331313010989 and 201331313011007.
It is not an unprimeable number, because it can be changed into a prime (201331313011093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51671253 + ... + 55430866.
It is an arithmetic number, because the mean of its divisors is an integer number (50332855498240).
Almost surely, 2201331313011033 is an apocalyptic number.
It is an amenable number.
201331313011033 is a deficient number, since it is larger than the sum of its proper divisors (108981927).
201331313011033 is a wasteful number, since it uses less digits than its factorization.
201331313011033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108981926.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 201331313011033 its reverse (330110313133102), we get a palindrome (531441626144135).
The spelling of 201331313011033 in words is "two hundred one trillion, three hundred thirty-one billion, three hundred thirteen million, eleven thousand, thirty-three".
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