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201331412304313 is a prime number
BaseRepresentation
bin101101110001110000011111…
…010100000000000110111001
3222101212002120021202220110211
4231301300133110000012321
5202342103213022214223
61552110212435511121
760256500040215304
oct5561603724000671
9871762507686424
10201331412304313
1159172199601715
121a6b74627584a1
138845617217525
1437a06c700db3b
15184215aab3d0d
hexb71c1f5001b9

201331412304313 has 2 divisors, whose sum is σ = 201331412304314. Its totient is φ = 201331412304312.

The previous prime is 201331412304307. The next prime is 201331412304509. The reversal of 201331412304313 is 313403214133102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 198711960689529 + 2619451614784 = 14096523^2 + 1618472^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201331412304313 is a prime.

It is not a weakly prime, because it can be changed into another prime (201331712304313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100665706152156 + 100665706152157.

It is an arithmetic number, because the mean of its divisors is an integer number (100665706152157).

Almost surely, 2201331412304313 is an apocalyptic number.

It is an amenable number.

201331412304313 is a deficient number, since it is larger than the sum of its proper divisors (1).

201331412304313 is an equidigital number, since it uses as much as digits as its factorization.

201331412304313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 201331412304313 its reverse (313403214133102), we get a palindrome (514734626437415).

The spelling of 201331412304313 in words is "two hundred one trillion, three hundred thirty-one billion, four hundred twelve million, three hundred four thousand, three hundred thirteen".