Base | Representation |
---|---|
bin | 11101010011000011011… |
… | …001110100100010011001 |
3 | 21010110201221110102011121 |
4 | 131103003121310202121 |
5 | 230441241143123231 |
6 | 4140524031325241 |
7 | 265313010211165 |
oct | 35230331644231 |
9 | 7113657412147 |
10 | 2013323020441 |
11 | 7069333a3287 |
12 | 286241980821 |
13 | 117b17834015 |
14 | 6d6340a1ca5 |
15 | 37587989311 |
hex | 1d4c3674899 |
2013323020441 has 4 divisors (see below), whose sum is σ = 2013374134800. Its totient is φ = 2013271906084.
The previous prime is 2013323020439. The next prime is 2013323020447. The reversal of 2013323020441 is 1440203233102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2013323020441 - 21 = 2013323020439 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013323020447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25498051 + ... + 25576888.
It is an arithmetic number, because the mean of its divisors is an integer number (503343533700).
Almost surely, 22013323020441 is an apocalyptic number.
It is an amenable number.
2013323020441 is a deficient number, since it is larger than the sum of its proper divisors (51114359).
2013323020441 is an equidigital number, since it uses as much as digits as its factorization.
2013323020441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51114358.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 2013323020441 its reverse (1440203233102), we get a palindrome (3453526253543).
The spelling of 2013323020441 in words is "two trillion, thirteen billion, three hundred twenty-three million, twenty thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •