Base | Representation |
---|---|
bin | 111100000000000… |
… | …1110010001111011 |
3 | 12012022102110212210 |
4 | 1320000032101323 |
5 | 13110402340121 |
6 | 531440310203 |
7 | 100614655320 |
oct | 17000162173 |
9 | 5168373783 |
10 | 2013324411 |
11 | 94351847a |
12 | 482312363 |
13 | 261161127 |
14 | 151566b47 |
15 | bbb45876 |
hex | 7800e47b |
2013324411 has 8 divisors (see below), whose sum is σ = 3067922944. Its totient is φ = 1150471080.
The previous prime is 2013324407. The next prime is 2013324413. The reversal of 2013324411 is 1144233102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2013324411 - 22 = 2013324407 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 95872591 = 2013324411 / (2 + 0 + 1 + 3 + 3 + 2 + 4 + 4 + 1 + 1).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013324413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47936275 + ... + 47936316.
It is an arithmetic number, because the mean of its divisors is an integer number (383490368).
Almost surely, 22013324411 is an apocalyptic number.
2013324411 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2013324411 is a deficient number, since it is larger than the sum of its proper divisors (1054598533).
2013324411 is an equidigital number, since it uses as much as digits as its factorization.
2013324411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95872601.
The product of its (nonzero) digits is 576, while the sum is 21.
The square root of 2013324411 is about 44870.0836972698. The cubic root of 2013324411 is about 1262.7128102654.
Adding to 2013324411 its reverse (1144233102), we get a palindrome (3157557513).
It can be divided in two parts, 20133 and 24411, that added together give a palindrome (44544).
The spelling of 2013324411 in words is "two billion, thirteen million, three hundred twenty-four thousand, four hundred eleven".
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