201333031000113 has 4 divisors (see below), whose sum is σ = 268444041333488. Its totient is φ = 134222020666740.

The previous prime is 201333031000091. The next prime is 201333031000139. The reversal of 201333031000113 is 311000130333102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 201333031000113 - 2⁸ = 201333030999857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 201333031000113.

It is not an unprimeable number, because it can be changed into a prime (201333031000313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33555505166683 + ... + 33555505166688.

It is an arithmetic number, because the mean of its divisors is an integer number (67111010333372).

Almost surely, 2^{201333031000113} is an apocalyptic number.

It is an amenable number.

201333031000113 is a deficient number, since it is larger than the sum of its proper divisors (67111010333375).

201333031000113 is an equidigital number, since it uses as much as digits as its factorization.

201333031000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67111010333374.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 201333031000113 its reverse (311000130333102), we get a palindrome (512333161333215).

The spelling of 201333031000113 in words is "two hundred one trillion, three hundred thirty-three billion, thirty-one million, one hundred thirteen", and thus it is an aban number.