Base | Representation |
---|---|
bin | 1011101110000001110… |
… | …0101110101000010011 |
3 | 201020200022200011020101 |
4 | 2323200130232220103 |
5 | 11244313013414102 |
6 | 232254104553231 |
7 | 20355150544342 |
oct | 2734034565023 |
9 | 636608604211 |
10 | 201334123027 |
11 | 78426955614 |
12 | 3302a482817 |
13 | 15ca784399b |
14 | 9a5d365b59 |
15 | 5385654e87 |
hex | 2ee072ea13 |
201334123027 has 2 divisors, whose sum is σ = 201334123028. Its totient is φ = 201334123026.
The previous prime is 201334123009. The next prime is 201334123031. The reversal of 201334123027 is 720321433102.
201334123027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201334123027 - 215 = 201334090259 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201334122986 and 201334123004.
It is not a weakly prime, because it can be changed into another prime (201334123007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100667061513 + 100667061514.
It is an arithmetic number, because the mean of its divisors is an integer number (100667061514).
Almost surely, 2201334123027 is an apocalyptic number.
201334123027 is a deficient number, since it is larger than the sum of its proper divisors (1).
201334123027 is an equidigital number, since it uses as much as digits as its factorization.
201334123027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 201334123027 its reverse (720321433102), we get a palindrome (921655556129).
The spelling of 201334123027 in words is "two hundred one billion, three hundred thirty-four million, one hundred twenty-three thousand, twenty-seven".
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