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2013342234121 is a prime number
BaseRepresentation
bin11101010011000100100…
…011000111011000001001
321010110210021121120101101
4131103010203013120021
5230441311102442441
64140525555221401
7265313332423561
oct35230443073011
97113707546341
102013342234121
11706943226859
122862482a7861
13117b1b80056a
146d636863da1
15375894d2231
hex1d4c48c7609

2013342234121 has 2 divisors, whose sum is σ = 2013342234122. Its totient is φ = 2013342234120.

The previous prime is 2013342234107. The next prime is 2013342234143. The reversal of 2013342234121 is 1214322433102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1231735946896 + 781606287225 = 1109836^2 + 884085^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013342234121 - 25 = 2013342234089 is a prime.

It is a super-4 number, since 4×20133422341214 (a number of 50 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2013342234121.

It is not a weakly prime, because it can be changed into another prime (2013342534121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006671117060 + 1006671117061.

It is an arithmetic number, because the mean of its divisors is an integer number (1006671117061).

Almost surely, 22013342234121 is an apocalyptic number.

It is an amenable number.

2013342234121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013342234121 is an equidigital number, since it uses as much as digits as its factorization.

2013342234121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 2013342234121 its reverse (1214322433102), we get a palindrome (3227664667223).

The spelling of 2013342234121 in words is "two trillion, thirteen billion, three hundred forty-two million, two hundred thirty-four thousand, one hundred twenty-one".