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2013343534003 = 3173889678981
BaseRepresentation
bin11101010011000100101…
…000000100101110110011
321010110210101001121111011
4131103010220010232303
5230441311421042003
64140530043131351
7265313346446404
oct35230450045663
97113711047434
102013343534003
11706943a3443a
12286248813b57
13117b1bb67119
146d636ac19ab
153758968c46d
hex1d4c4a04bb3

2013343534003 has 8 divisors (see below), whose sum is σ = 2106759829376. Its totient is φ = 1921706596800.

The previous prime is 2013343533967. The next prime is 2013343534049. The reversal of 2013343534003 is 3004353433102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013343534003 - 213 = 2013343525811 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is not an unprimeable number, because it can be changed into a prime (2013043534003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 444837228 + ... + 444841753.

It is an arithmetic number, because the mean of its divisors is an integer number (263344978672).

Almost surely, 22013343534003 is an apocalyptic number.

2013343534003 is a deficient number, since it is larger than the sum of its proper divisors (93416295373).

2013343534003 is an equidigital number, since it uses as much as digits as its factorization.

2013343534003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 889679085.

The product of its (nonzero) digits is 38880, while the sum is 31.

Adding to 2013343534003 its reverse (3004353433102), we get a palindrome (5017696967105).

The spelling of 2013343534003 in words is "two trillion, thirteen billion, three hundred forty-three million, five hundred thirty-four thousand, three".

Divisors: 1 31 73 2263 889678981 27580048411 64946565613 2013343534003