Base | Representation |
---|---|
bin | 101101110001110011010011… |
… | …111010101011111001100001 |
3 | 222101212101101110022212120011 |
4 | 231301303103322223321201 |
5 | 202342130414220002113 |
6 | 1552111433240044521 |
7 | 60256635112143325 |
oct | 5561632372537141 |
9 | 871771343285504 |
10 | 201334442344033 |
11 | 59173503a1a379 |
12 | 1a6b7b69463741 |
13 | 88459aabb8b3b |
14 | 37a08d35d5985 |
15 | 1842286add63d |
hex | b71cd3eabe61 |
201334442344033 has 2 divisors, whose sum is σ = 201334442344034. Its totient is φ = 201334442344032.
The previous prime is 201334442344027. The next prime is 201334442344037. The reversal of 201334442344033 is 330443244433102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 200219585110609 + 1114857233424 = 14149897^2 + 1055868^2 .
It is a cyclic number.
It is not a de Polignac number, because 201334442344033 - 217 = 201334442212961 is a prime.
It is not a weakly prime, because it can be changed into another prime (201334442344037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100667221172016 + 100667221172017.
It is an arithmetic number, because the mean of its divisors is an integer number (100667221172017).
Almost surely, 2201334442344033 is an apocalyptic number.
It is an amenable number.
201334442344033 is a deficient number, since it is larger than the sum of its proper divisors (1).
201334442344033 is an equidigital number, since it uses as much as digits as its factorization.
201334442344033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 995328, while the sum is 40.
Adding to 201334442344033 its reverse (330443244433102), we get a palindrome (531777686777135).
The spelling of 201334442344033 in words is "two hundred one trillion, three hundred thirty-four billion, four hundred forty-two million, three hundred forty-four thousand, thirty-three".
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