Base | Representation |
---|---|
bin | 11101010011000100101… |
… | …100001100111000111001 |
3 | 21010110210110002120200212 |
4 | 131103010230030320321 |
5 | 230441312210202433 |
6 | 4140530122240505 |
7 | 265313361604034 |
oct | 35230454147071 |
9 | 7113713076625 |
10 | 2013344615993 |
11 | 706944603347 |
12 | 286249056135 |
13 | 117b1c155759 |
14 | 6d636cc401b |
15 | 37589802d48 |
hex | 1d4c4b0ce39 |
2013344615993 has 2 divisors, whose sum is σ = 2013344615994. Its totient is φ = 2013344615992.
The previous prime is 2013344615923. The next prime is 2013344616001. The reversal of 2013344615993 is 3995164433102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1450586586409 + 562758029584 = 1204403^2 + 750172^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013344615993 - 212 = 2013344611897 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013344615923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006672307996 + 1006672307997.
It is an arithmetic number, because the mean of its divisors is an integer number (1006672307997).
Almost surely, 22013344615993 is an apocalyptic number.
It is an amenable number.
2013344615993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013344615993 is an equidigital number, since it uses as much as digits as its factorization.
2013344615993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 50.
The spelling of 2013344615993 in words is "two trillion, thirteen billion, three hundred forty-four million, six hundred fifteen thousand, nine hundred ninety-three".
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