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201340213234 = 2100670106617
BaseRepresentation
bin1011101110000011001…
…1111101011111110010
3201020200202010120102121
42323200303331133302
511244321043310414
6232254443304454
720355253401136
oct2734063753762
9636622116377
10201340213234
117842a335246
123303051b12a
1315ca8b96a64
149a600ad3c6
155385e59724
hex2ee0cfd7f2

201340213234 has 4 divisors (see below), whose sum is σ = 302010319854. Its totient is φ = 100670106616.

The previous prime is 201340213223. The next prime is 201340213267. The reversal of 201340213234 is 432312043102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 186939493225 + 14400720009 = 432365^2 + 120003^2 .

It is a super-2 number, since 2×2013402132342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201340213199 and 201340213208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50335053307 + ... + 50335053310.

Almost surely, 2201340213234 is an apocalyptic number.

201340213234 is a deficient number, since it is larger than the sum of its proper divisors (100670106620).

201340213234 is a wasteful number, since it uses less digits than its factorization.

201340213234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100670106619.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 201340213234 its reverse (432312043102), we get a palindrome (633652256336).

The spelling of 201340213234 in words is "two hundred one billion, three hundred forty million, two hundred thirteen thousand, two hundred thirty-four".

Divisors: 1 2 100670106617 201340213234