Base | Representation |
---|---|
bin | 1011101110000011010… |
… | …0011101001110100011 |
3 | 201020200202101011201021 |
4 | 2323200310131032203 |
5 | 11244321111440303 |
6 | 232254450150311 |
7 | 20355254452066 |
oct | 2734064351643 |
9 | 636622334637 |
10 | 201340343203 |
11 | 7842a41395a |
12 | 33030582397 |
13 | 15ca8c10c6c |
14 | 9a601048dd |
15 | 5385e82ebd |
hex | 2ee0d1d3a3 |
201340343203 has 4 divisors (see below), whose sum is σ = 202362375600. Its totient is φ = 200318310808.
The previous prime is 201340343167. The next prime is 201340343227. The reversal of 201340343203 is 302343043102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 302343043102 = 2 ⋅151171521551.
It is a cyclic number.
It is not a de Polignac number, because 201340343203 - 29 = 201340342691 is a prime.
It is a super-2 number, since 2×2013403432032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (201340343803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511015903 + ... + 511016296.
It is an arithmetic number, because the mean of its divisors is an integer number (50590593900).
Almost surely, 2201340343203 is an apocalyptic number.
201340343203 is a deficient number, since it is larger than the sum of its proper divisors (1022032397).
201340343203 is a wasteful number, since it uses less digits than its factorization.
201340343203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1022032396.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 201340343203 its reverse (302343043102), we get a palindrome (503683386305).
The spelling of 201340343203 in words is "two hundred one billion, three hundred forty million, three hundred forty-three thousand, two hundred three".
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