20134101002011 has 4 divisors (see below), whose sum is σ = 20161346065000. Its totient is φ = 20106855939024.

The previous prime is 20134101001981. The next prime is 20134101002017. The reversal of 20134101002011 is 11020010143102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20134101002011 - 2⁵ = 20134101001979 is a prime.

It is a super-3 number, since 3×20134101002011³ (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20134101002017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13622530386 + ... + 13622531863.

It is an arithmetic number, because the mean of its divisors is an integer number (5040336516250).

Almost surely, 2^{20134101002011} is an apocalyptic number.

20134101002011 is a deficient number, since it is larger than the sum of its proper divisors (27245062989).

20134101002011 is an equidigital number, since it uses as much as digits as its factorization.

20134101002011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27245062988.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 20134101002011 its reverse (11020010143102), we get a palindrome (31154111145113).

The spelling of 20134101002011 in words is "twenty trillion, one hundred thirty-four billion, one hundred one million, two thousand, eleven".