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2013410235107 is a prime number
BaseRepresentation
bin11101010011001000100…
…110100001001011100011
321010110222000120101012102
4131103020212201023203
5230441431010010412
64140540424521015
7265315116423305
oct35231046411343
97113860511172
102013410235107
11706978651a17
1228626702016b
13117b2c91c22b
146d6418c5975
15375904658c2
hex1d4c89a12e3

2013410235107 has 2 divisors, whose sum is σ = 2013410235108. Its totient is φ = 2013410235106.

The previous prime is 2013410234999. The next prime is 2013410235149. The reversal of 2013410235107 is 7015320143102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013410235107 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2013410235107.

It is not a weakly prime, because it can be changed into another prime (2013410235197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006705117553 + 1006705117554.

It is an arithmetic number, because the mean of its divisors is an integer number (1006705117554).

Almost surely, 22013410235107 is an apocalyptic number.

2013410235107 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013410235107 is an equidigital number, since it uses as much as digits as its factorization.

2013410235107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 2013410235107 its reverse (7015320143102), we get a palindrome (9028730378209).

The spelling of 2013410235107 in words is "two trillion, thirteen billion, four hundred ten million, two hundred thirty-five thousand, one hundred seven".