Base | Representation |
---|---|
bin | 11101010011001000100… |
… | …111001011111110100001 |
3 | 21010110222000220021122210 |
4 | 131103020213023332201 |
5 | 230441431031113101 |
6 | 4140540432352333 |
7 | 265315121053335 |
oct | 35231047137641 |
9 | 7113860807583 |
10 | 2013410410401 |
11 | 706978761695 |
12 | 2862670a56a9 |
13 | 117b2c980c60 |
14 | 6d64192d7c5 |
15 | 3759049c7d6 |
hex | 1d4c89cbfa1 |
2013410410401 has 32 divisors (see below), whose sum is σ = 2898344913408. Its totient is φ = 1235896945920.
The previous prime is 2013410410367. The next prime is 2013410410469. The reversal of 2013410410401 is 1040140143102.
It is not a de Polignac number, because 2013410410401 - 29 = 2013410409889 is a prime.
It is a super-2 number, since 2×20134104104012 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2013410418401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 116259195 + ... + 116276511.
It is an arithmetic number, because the mean of its divisors is an integer number (90573278544).
Almost surely, 22013410410401 is an apocalyptic number.
It is an amenable number.
2013410410401 is a deficient number, since it is larger than the sum of its proper divisors (884934503007).
2013410410401 is a wasteful number, since it uses less digits than its factorization.
2013410410401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24681.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 2013410410401 its reverse (1040140143102), we get a palindrome (3053550553503).
The spelling of 2013410410401 in words is "two trillion, thirteen billion, four hundred ten million, four hundred ten thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •