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201341304937 is a prime number
BaseRepresentation
bin1011101110000011100…
…0001000000001101001
3201020200211012000222001
42323200320020001221
511244321333224222
6232254522531001
720355265566013
oct2734070100151
9636624160861
10201341304937
117842aa10483
1233030966a61
1315ca9189936
149a602b51b3
1553860c2e27
hex2ee0e08069

201341304937 has 2 divisors, whose sum is σ = 201341304938. Its totient is φ = 201341304936.

The previous prime is 201341304889. The next prime is 201341304949. The reversal of 201341304937 is 739403143102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 184065882841 + 17275422096 = 429029^2 + 131436^2 .

It is a cyclic number.

It is not a de Polignac number, because 201341304937 - 215 = 201341272169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201341304896 and 201341304905.

It is not a weakly prime, because it can be changed into another prime (201341302937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670652468 + 100670652469.

It is an arithmetic number, because the mean of its divisors is an integer number (100670652469).

Almost surely, 2201341304937 is an apocalyptic number.

It is an amenable number.

201341304937 is a deficient number, since it is larger than the sum of its proper divisors (1).

201341304937 is an equidigital number, since it uses as much as digits as its factorization.

201341304937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 37.

The spelling of 201341304937 in words is "two hundred one billion, three hundred forty-one million, three hundred four thousand, nine hundred thirty-seven".