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2013413201003 = 15111332503773
BaseRepresentation
bin11101010011001000110…
…001110101010001101011
321010110222020011001122102
4131103020301311101223
5230441432234413003
64140541012244015
7265315153555241
oct35231061652153
97113866131572
102013413201003
1170697a298276
1228626801060b
13117b3041a1b9
146d642058791
153759084e588
hex1d4c8c7546b

2013413201003 has 4 divisors (see below), whose sum is σ = 2014745706288. Its totient is φ = 2012080695720.

The previous prime is 2013413200973. The next prime is 2013413201011. The reversal of 2013413201003 is 3001023143102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013413201003 - 238 = 1738535294059 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013413201083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 666250376 + ... + 666253397.

It is an arithmetic number, because the mean of its divisors is an integer number (503686426572).

Almost surely, 22013413201003 is an apocalyptic number.

2013413201003 is a deficient number, since it is larger than the sum of its proper divisors (1332505285).

2013413201003 is a wasteful number, since it uses less digits than its factorization.

2013413201003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1332505284.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2013413201003 its reverse (3001023143102), we get a palindrome (5014436344105).

The spelling of 2013413201003 in words is "two trillion, thirteen billion, four hundred thirteen million, two hundred one thousand, three".

Divisors: 1 1511 1332503773 2013413201003