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201341343331402 = 2100670671665701
BaseRepresentation
bin101101110001111001101111…
…001111110111010001001010
3222101220001012101202100112221
4231301321233033313101022
5202342234032343101102
61552114534120124254
760260301116442121
oct5561715717672112
9871801171670487
10201341343331402
115917642539731a
121a6b937460668a
13884653a835811
1437a0d89d3aab8
15184253c89a637
hexb71e6f3f744a

201341343331402 has 4 divisors (see below), whose sum is σ = 302012014997106. Its totient is φ = 100670671665700.

The previous prime is 201341343331399. The next prime is 201341343331441. The reversal of 201341343331402 is 204133343143102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 200862619105201 + 478724226201 = 14172601^2 + 691899^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50335335832849 + ... + 50335335832852.

Almost surely, 2201341343331402 is an apocalyptic number.

201341343331402 is a deficient number, since it is larger than the sum of its proper divisors (100670671665704).

201341343331402 is a wasteful number, since it uses less digits than its factorization.

201341343331402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100670671665703.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 201341343331402 its reverse (204133343143102), we get a palindrome (405474686474504).

The spelling of 201341343331402 in words is "two hundred one trillion, three hundred forty-one billion, three hundred forty-three million, three hundred thirty-one thousand, four hundred two".

Divisors: 1 2 100670671665701 201341343331402