Base | Representation |
---|---|
bin | 11101010011001001011… |
… | …111011011000010011001 |
3 | 21010111000001122020112121 |
4 | 131103021133123002121 |
5 | 230441443314332103 |
6 | 4140542120341241 |
7 | 265315360262242 |
oct | 35231137330231 |
9 | 7114001566477 |
10 | 2013425152153 |
11 | 706986010358 |
12 | 286270014821 |
13 | 117b32a42b9c |
14 | 6d643889cc9 |
15 | 375919106bd |
hex | 1d4c97db099 |
2013425152153 has 4 divisors (see below), whose sum is σ = 2013518487220. Its totient is φ = 2013331817088.
The previous prime is 2013425152103. The next prime is 2013425152177. The reversal of 2013425152153 is 3512515243102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1154739369744 + 858685782409 = 1074588^2 + 926653^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013425152153 - 217 = 2013425021081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013425152103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46635168 + ... + 46678321.
It is an arithmetic number, because the mean of its divisors is an integer number (503379621805).
Almost surely, 22013425152153 is an apocalyptic number.
It is an amenable number.
2013425152153 is a deficient number, since it is larger than the sum of its proper divisors (93335067).
2013425152153 is an equidigital number, since it uses as much as digits as its factorization.
2013425152153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93335066.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 2013425152153 in words is "two trillion, thirteen billion, four hundred twenty-five million, one hundred fifty-two thousand, one hundred fifty-three".
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