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201343355401 = 895122493951
BaseRepresentation
bin1011101110000011111…
…1111100101000001001
3201020200222001012200011
42323200333330220021
511244322344333101
6232255034511521
720355322166026
oct2734077745011
9636628035604
10201343355401
1178431090a81
12330315955a1
1315ca9727026
149a6068a54d
15538637a751
hex2ee0ffca09

201343355401 has 4 divisors (see below), whose sum is σ = 201365858304. Its totient is φ = 201320852500.

The previous prime is 201343355393. The next prime is 201343355429. The reversal of 201343355401 is 104553343102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201343355401 - 23 = 201343355393 is a prime.

It is a super-3 number, since 3×2013433554013 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201343355491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11238025 + ... + 11255926.

It is an arithmetic number, because the mean of its divisors is an integer number (50341464576).

Almost surely, 2201343355401 is an apocalyptic number.

It is an amenable number.

201343355401 is a deficient number, since it is larger than the sum of its proper divisors (22502903).

201343355401 is an equidigital number, since it uses as much as digits as its factorization.

201343355401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22502902.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 201343355401 its reverse (104553343102), we get a palindrome (305896698503).

The spelling of 201343355401 in words is "two hundred one billion, three hundred forty-three million, three hundred fifty-five thousand, four hundred one".

Divisors: 1 8951 22493951 201343355401