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2013442205041 = 37105151776743
BaseRepresentation
bin11101010011001010100…
…000011110010101110001
321010111001020201121201001
4131103022200132111301
5230442012201030131
64140543530042001
7265315655235151
oct35231240362561
97114036647631
102013442205041
117069946a8453
12286275879301
13117b36433a57
146d645c48761
153759317d261
hex1d4ca81e571

2013442205041 has 8 divisors (see below), whose sum is σ = 2069827118144. Its totient is φ = 1957160847600.

The previous prime is 2013442205029. The next prime is 2013442205057. The reversal of 2013442205041 is 1405022443102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013442205041 - 213 = 2013442196849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013442203041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25849485 + ... + 25927258.

It is an arithmetic number, because the mean of its divisors is an integer number (258728389768).

Almost surely, 22013442205041 is an apocalyptic number.

It is an amenable number.

2013442205041 is a deficient number, since it is larger than the sum of its proper divisors (56384913103).

2013442205041 is a wasteful number, since it uses less digits than its factorization.

2013442205041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51777831.

The product of its (nonzero) digits is 7680, while the sum is 28.

Adding to 2013442205041 its reverse (1405022443102), we get a palindrome (3418464648143).

The spelling of 2013442205041 in words is "two trillion, thirteen billion, four hundred forty-two million, two hundred five thousand, forty-one".

Divisors: 1 37 1051 38887 51776743 1915739491 54417356893 2013442205041