Base | Representation |
---|---|
bin | 11101010011001110010… |
… | …000001110000110100001 |
3 | 21010111012121222122000112 |
4 | 131103032100032012201 |
5 | 230442124243144324 |
6 | 4140554053101105 |
7 | 265320350363465 |
oct | 35231620160641 |
9 | 7114177878015 |
10 | 2013505053089 |
11 | 706a17124092 |
12 | 286292927795 |
13 | 117b4646a14a |
14 | 6d6503284a5 |
15 | 37598944c0e |
hex | 1d4ce40e1a1 |
2013505053089 has 2 divisors, whose sum is σ = 2013505053090. Its totient is φ = 2013505053088.
The previous prime is 2013505053067. The next prime is 2013505053127. The reversal of 2013505053089 is 9803505053102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1586289870400 + 427215182689 = 1259480^2 + 653617^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013505053089 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013505056089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006752526544 + 1006752526545.
It is an arithmetic number, because the mean of its divisors is an integer number (1006752526545).
Almost surely, 22013505053089 is an apocalyptic number.
It is an amenable number.
2013505053089 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013505053089 is an equidigital number, since it uses as much as digits as its factorization.
2013505053089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 2013505053089 in words is "two trillion, thirteen billion, five hundred five million, fifty-three thousand, eighty-nine".
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