Base | Representation |
---|---|
bin | 101101110010000011000111… |
… | …101011010110011000011011 |
3 | 222101221000012102212221122012 |
4 | 231302003013223112120123 |
5 | 202342420200204210311 |
6 | 1552123321451020135 |
7 | 60261105546202454 |
oct | 5562030753263033 |
9 | 871830172787565 |
10 | 201351416866331 |
11 | 5917a7246671a6 |
12 | 1a6bb30613a64b |
13 | 884748482b784 |
14 | 37a1663b6212b |
15 | 184292be3178b |
hex | b720c7ad661b |
201351416866331 has 2 divisors, whose sum is σ = 201351416866332. Its totient is φ = 201351416866330.
The previous prime is 201351416866289. The next prime is 201351416866343. The reversal of 201351416866331 is 133668614153102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201351416866331 - 234 = 201334236997147 is a prime.
It is a super-2 number, since 2×2013514168663312 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 201351416866331.
It is not a weakly prime, because it can be changed into another prime (201351416866361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100675708433165 + 100675708433166.
It is an arithmetic number, because the mean of its divisors is an integer number (100675708433166).
Almost surely, 2201351416866331 is an apocalyptic number.
201351416866331 is a deficient number, since it is larger than the sum of its proper divisors (1).
201351416866331 is an equidigital number, since it uses as much as digits as its factorization.
201351416866331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1866240, while the sum is 50.
The spelling of 201351416866331 in words is "two hundred one trillion, three hundred fifty-one billion, four hundred sixteen million, eight hundred sixty-six thousand, three hundred thirty-one".
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