Base | Representation |
---|---|
bin | 1001001010000010010001… |
… | …00010100110111011100001 |
3 | 2122021222121010002012120121 |
4 | 10211001020202212323201 |
5 | 10114402034032344203 |
6 | 110454210034240241 |
7 | 4145531303360104 |
oct | 445011042467341 |
9 | 78258533065517 |
10 | 20136023715553 |
11 | 6463704495889 |
12 | 23125b5726081 |
13 | b30a851389a5 |
14 | 4d883574a73b |
15 | 24dbb69690bd |
hex | 1250488a6ee1 |
20136023715553 has 8 divisors (see below), whose sum is σ = 20294828828672. Its totient is φ = 19977222567456.
The previous prime is 20136023715529. The next prime is 20136023715559. The reversal of 20136023715553 is 35551732063102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20136023715553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20136023715559) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9654676 + ... + 11553562.
It is an arithmetic number, because the mean of its divisors is an integer number (2536853603584).
Almost surely, 220136023715553 is an apocalyptic number.
It is an amenable number.
20136023715553 is a deficient number, since it is larger than the sum of its proper divisors (158805113119).
20136023715553 is a wasteful number, since it uses less digits than its factorization.
20136023715553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1982511.
The product of its (nonzero) digits is 567000, while the sum is 43.
Adding to 20136023715553 its reverse (35551732063102), we get a palindrome (55687755778655).
The spelling of 20136023715553 in words is "twenty trillion, one hundred thirty-six billion, twenty-three million, seven hundred fifteen thousand, five hundred fifty-three".
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