2014012143361 has 4 divisors (see below), whose sum is σ = 2014061757232. Its totient is φ = 2013962529492.

The previous prime is 2014012143263. The next prime is 2014012143397. The reversal of 2014012143361 is 1633412104102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2014012143361 - 2¹⁹ = 2014011619073 is a prime.

It is a super-3 number, since 3×2014012143361³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2014013143361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24745995 + ... + 24827248.

It is an arithmetic number, because the mean of its divisors is an integer number (503515439308).

Almost surely, 2^{2014012143361} is an apocalyptic number.

It is an amenable number.

2014012143361 is a deficient number, since it is larger than the sum of its proper divisors (49613871).

2014012143361 is an equidigital number, since it uses as much as digits as its factorization.

2014012143361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49613870.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 2014012143361 its reverse (1633412104102), we get a palindrome (3647424247463).

The spelling of 2014012143361 in words is "two trillion, fourteen billion, twelve million, one hundred forty-three thousand, three hundred sixty-one".