Base | Representation |
---|---|
bin | 11101010011101101001… |
… | …000000101011011010001 |
3 | 21010112112201121202221120 |
4 | 131103231020011123101 |
5 | 230444204342422342 |
6 | 4141121314512453 |
7 | 265336240105053 |
oct | 35235510053321 |
9 | 7115481552846 |
10 | 2014023014097 |
11 | 707162538936 |
12 | 2863b8295729 |
13 | 117bc9870553 |
14 | 6d69d0378d3 |
15 | 375c9159aec |
hex | 1d4ed2056d1 |
2014023014097 has 4 divisors (see below), whose sum is σ = 2685364018800. Its totient is φ = 1342682009396.
The previous prime is 2014023014089. The next prime is 2014023014117. The reversal of 2014023014097 is 7904103204102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2014023014097 - 23 = 2014023014089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2014023014027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335670502347 + ... + 335670502352.
It is an arithmetic number, because the mean of its divisors is an integer number (671341004700).
Almost surely, 22014023014097 is an apocalyptic number.
It is an amenable number.
2014023014097 is a deficient number, since it is larger than the sum of its proper divisors (671341004703).
2014023014097 is an equidigital number, since it uses as much as digits as its factorization.
2014023014097 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 671341004702.
The product of its (nonzero) digits is 12096, while the sum is 33.
Adding to 2014023014097 its reverse (7904103204102), we get a palindrome (9918126218199).
The spelling of 2014023014097 in words is "two trillion, fourteen billion, twenty-three million, fourteen thousand, ninety-seven".
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