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2014074013561 is a prime number
BaseRepresentation
bin11101010011110000001…
…010101000011101111001
321010112200021120211001121
4131103300022220131321
5230444310421413221
64141130335545241
7265340426434411
oct35236012503571
97115607524047
102014074013561
11707189301555
1228641138b221
13117c072b884c
146d6a5b11641
15375cd880a41
hex1d4f02a8779

2014074013561 has 2 divisors, whose sum is σ = 2014074013562. Its totient is φ = 2014074013560.

The previous prime is 2014074013543. The next prime is 2014074013571. The reversal of 2014074013561 is 1653104704102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1658119782400 + 355954231161 = 1287680^2 + 596619^2 .

It is a cyclic number.

It is not a de Polignac number, because 2014074013561 - 223 = 2014065624953 is a prime.

It is not a weakly prime, because it can be changed into another prime (2014074013571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007037006780 + 1007037006781.

It is an arithmetic number, because the mean of its divisors is an integer number (1007037006781).

Almost surely, 22014074013561 is an apocalyptic number.

It is an amenable number.

2014074013561 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014074013561 is an equidigital number, since it uses as much as digits as its factorization.

2014074013561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 2014074013561 its reverse (1653104704102), we get a palindrome (3667178717663).

The spelling of 2014074013561 in words is "two trillion, fourteen billion, seventy-four million, thirteen thousand, five hundred sixty-one".