Base | Representation |
---|---|
bin | 11101010100000101011… |
… | …001111101010010101001 |
3 | 21010120121010002201021001 |
4 | 131110011121331102221 |
5 | 231001023132240203 |
6 | 4141225545315001 |
7 | 265352314322533 |
oct | 35240531752251 |
9 | 7116533081231 |
10 | 2014430352553 |
11 | 707351466293 |
12 | 2864b0795a61 |
13 | 117c63081118 |
14 | 6d6db18c853 |
15 | 375eecbc91d |
hex | 1d50567d4a9 |
2014430352553 has 2 divisors, whose sum is σ = 2014430352554. Its totient is φ = 2014430352552.
The previous prime is 2014430352541. The next prime is 2014430352563. The reversal of 2014430352553 is 3552530344102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1296872272809 + 717558079744 = 1138803^2 + 847088^2 .
It is a cyclic number.
It is not a de Polignac number, because 2014430352553 - 229 = 2013893481641 is a prime.
It is not a weakly prime, because it can be changed into another prime (2014430352563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007215176276 + 1007215176277.
It is an arithmetic number, because the mean of its divisors is an integer number (1007215176277).
Almost surely, 22014430352553 is an apocalyptic number.
It is an amenable number.
2014430352553 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014430352553 is an equidigital number, since it uses as much as digits as its factorization.
2014430352553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 2014430352553 its reverse (3552530344102), we get a palindrome (5566960696655).
The spelling of 2014430352553 in words is "two trillion, fourteen billion, four hundred thirty million, three hundred fifty-two thousand, five hundred fifty-three".
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