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20145414111497 is a prime number
BaseRepresentation
bin1001001010010011110000…
…10000001000000100001001
32122022212211112202202010222
410211021320100020010021
510120030302003031442
6110502401523115425
74146313066412543
oct445117020100411
978285745682128
1020145414111497
116467693092294
122314396512b75
13b31920746cac
144d9086946693
1524e06605d8d2
hex125278408109

20145414111497 has 2 divisors, whose sum is σ = 20145414111498. Its totient is φ = 20145414111496.

The previous prime is 20145414111467. The next prime is 20145414111569. The reversal of 20145414111497 is 79411141454102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16181157901561 + 3964256209936 = 4022581^2 + 1991044^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20145414111497 is a prime.

It is a super-3 number, since 3×201454141114973 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (20145414111467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072707055748 + 10072707055749.

It is an arithmetic number, because the mean of its divisors is an integer number (10072707055749).

Almost surely, 220145414111497 is an apocalyptic number.

It is an amenable number.

20145414111497 is a deficient number, since it is larger than the sum of its proper divisors (1).

20145414111497 is an equidigital number, since it uses as much as digits as its factorization.

20145414111497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 161280, while the sum is 44.

Adding to 20145414111497 its reverse (79411141454102), we get a palindrome (99556555565599).

The spelling of 20145414111497 in words is "twenty trillion, one hundred forty-five billion, four hundred fourteen million, one hundred eleven thousand, four hundred ninety-seven".