Base | Representation |
---|---|
bin | 10010110000110010… |
… | …111110111011010011 |
3 | 1221000000022001201111 |
4 | 102300302332323103 |
5 | 312224340233042 |
6 | 13131023114151 |
7 | 1312144244164 |
oct | 226062767323 |
9 | 57000261644 |
10 | 20146024147 |
11 | 85a89a6137 |
12 | 3aa2a42957 |
13 | 1b90a13c62 |
14 | d9185776b |
15 | 7cd9b2517 |
hex | 4b0cbeed3 |
20146024147 has 2 divisors, whose sum is σ = 20146024148. Its totient is φ = 20146024146.
The previous prime is 20146024111. The next prime is 20146024177. The reversal of 20146024147 is 74142064102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20146024147 is a prime.
It is not a weakly prime, because it can be changed into another prime (20146024177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10073012073 + 10073012074.
It is an arithmetic number, because the mean of its divisors is an integer number (10073012074).
Almost surely, 220146024147 is an apocalyptic number.
20146024147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20146024147 is an equidigital number, since it uses as much as digits as its factorization.
20146024147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 20146024147 its reverse (74142064102), we get a palindrome (94288088249).
The spelling of 20146024147 in words is "twenty billion, one hundred forty-six million, twenty-four thousand, one hundred forty-seven".
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