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2015014483 is a prime number
BaseRepresentation
bin111100000011010…
…1010111001010011
312012102121100020001
41320012222321103
513111320430413
6531540430431
7100635224536
oct17006527123
95172540201
102015014483
11944472229
124829a8417
13261603481
14151886a1d
15bbd7b4dd
hex781aae53

2015014483 has 2 divisors, whose sum is σ = 2015014484. Its totient is φ = 2015014482.

The previous prime is 2015014457. The next prime is 2015014541. The reversal of 2015014483 is 3844105102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2015014483 - 221 = 2012917331 is a prime.

It is not a weakly prime, because it can be changed into another prime (2015014423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007507241 + 1007507242.

It is an arithmetic number, because the mean of its divisors is an integer number (1007507242).

Almost surely, 22015014483 is an apocalyptic number.

2015014483 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015014483 is an equidigital number, since it uses as much as digits as its factorization.

2015014483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

The square root of 2015014483 is about 44888.9126956758. The cubic root of 2015014483 is about 1263.0660367807.

Adding to 2015014483 its reverse (3844105102), we get a palindrome (5859119585).

The spelling of 2015014483 in words is "two billion, fifteen million, fourteen thousand, four hundred eighty-three".