Base | Representation |
---|---|
bin | 1001001010011110011000… |
… | …11011000100010101010001 |
3 | 2122100102120021201120101002 |
4 | 10211033030123010111101 |
5 | 10120123444013430413 |
6 | 110505144114351345 |
7 | 4146604366222454 |
oct | 445171433042521 |
9 | 78312507646332 |
10 | 20151121233233 |
11 | 646a051663321 |
12 | 231550988b555 |
13 | b3231cc396c3 |
14 | 4d94688b749b |
15 | 24e29c0e2958 |
hex | 1253cc6c4551 |
20151121233233 has 2 divisors, whose sum is σ = 20151121233234. Its totient is φ = 20151121233232.
The previous prime is 20151121233181. The next prime is 20151121233247. The reversal of 20151121233233 is 33233212115102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15414787311889 + 4736333921344 = 3926167^2 + 2176312^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20151121233233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20151121233196 and 20151121233205.
It is not a weakly prime, because it can be changed into another prime (20151121233253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10075560616616 + 10075560616617.
It is an arithmetic number, because the mean of its divisors is an integer number (10075560616617).
Almost surely, 220151121233233 is an apocalyptic number.
It is an amenable number.
20151121233233 is a deficient number, since it is larger than the sum of its proper divisors (1).
20151121233233 is an equidigital number, since it uses as much as digits as its factorization.
20151121233233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 20151121233233 its reverse (33233212115102), we get a palindrome (53384333348335).
The spelling of 20151121233233 in words is "twenty trillion, one hundred fifty-one billion, one hundred twenty-one million, two hundred thirty-three thousand, two hundred thirty-three".
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