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2015161374241 is a prime number
BaseRepresentation
bin11101010100110000111…
…110100101011000100001
321010122111001122110111101
4131110300332211120201
5231004022302433431
64141430301514401
7265406402026231
oct35246076453041
97118431573441
102015161374241
11707697073744
12286675572a01
1311804b662532
146d76a2bdcc1
153764406b961
hex1d530fa5621

2015161374241 has 2 divisors, whose sum is σ = 2015161374242. Its totient is φ = 2015161374240.

The previous prime is 2015161374227. The next prime is 2015161374263. The reversal of 2015161374241 is 1424731615102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1851039159841 + 164122214400 = 1360529^2 + 405120^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2015161374241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2015161374241.

It is not a weakly prime, because it can be changed into another prime (2015161374041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007580687120 + 1007580687121.

It is an arithmetic number, because the mean of its divisors is an integer number (1007580687121).

Almost surely, 22015161374241 is an apocalyptic number.

It is an amenable number.

2015161374241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015161374241 is an equidigital number, since it uses as much as digits as its factorization.

2015161374241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 37.

Adding to 2015161374241 its reverse (1424731615102), we get a palindrome (3439892989343).

The spelling of 2015161374241 in words is "two trillion, fifteen billion, one hundred sixty-one million, three hundred seventy-four thousand, two hundred forty-one".