Base | Representation |
---|---|
bin | 1011101110101110011… |
… | …0001100100001000001 |
3 | 201021011100121022122122 |
4 | 2323223212030201001 |
5 | 11300203403412423 |
6 | 232324425414025 |
7 | 20362611355436 |
oct | 2735346144101 |
9 | 637140538578 |
10 | 201521154113 |
11 | 7851248a864 |
12 | 3308103a315 |
13 | 16007509c76 |
14 | 9a7a12db8d |
15 | 5396c9b8c8 |
hex | 2eeb98c841 |
201521154113 has 2 divisors, whose sum is σ = 201521154114. Its totient is φ = 201521154112.
The previous prime is 201521154071. The next prime is 201521154217. The reversal of 201521154113 is 311451125102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152031367744 + 49489786369 = 389912^2 + 222463^2 .
It is a cyclic number.
It is not a de Polignac number, because 201521154113 - 230 = 200447412289 is a prime.
It is a super-2 number, since 2×2015211541132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201521184113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100760577056 + 100760577057.
It is an arithmetic number, because the mean of its divisors is an integer number (100760577057).
Almost surely, 2201521154113 is an apocalyptic number.
It is an amenable number.
201521154113 is a deficient number, since it is larger than the sum of its proper divisors (1).
201521154113 is an equidigital number, since it uses as much as digits as its factorization.
201521154113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 201521154113 its reverse (311451125102), we get a palindrome (512972279215).
The spelling of 201521154113 in words is "two hundred one billion, five hundred twenty-one million, one hundred fifty-four thousand, one hundred thirteen".
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