Base | Representation |
---|---|
bin | 1001001010100000110001… |
… | …11001000001000110001001 |
3 | 2122100112212200202122001101 |
4 | 10211100120321001012021 |
5 | 10120134110430341323 |
6 | 110505515304021401 |
7 | 4146651234653500 |
oct | 445203071010611 |
9 | 78315780678041 |
10 | 20152404152713 |
11 | 646a64a854758 |
12 | 2315807461861 |
13 | b32495974061 |
14 | 4d954b02d837 |
15 | 24e324a5bdad |
hex | 125418e41189 |
20152404152713 has 24 divisors (see below), whose sum is σ = 23990439828960. Its totient is φ = 16869901809600.
The previous prime is 20152404152659. The next prime is 20152404152833. The reversal of 20152404152713 is 31725140425102.
It is a de Polignac number, because none of the positive numbers 2k-20152404152713 is a prime.
It is a super-2 number, since 2×201524041527132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20152404150713) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18559413 + ... + 19615213.
It is an arithmetic number, because the mean of its divisors is an integer number (999601659540).
Almost surely, 220152404152713 is an apocalyptic number.
It is an amenable number.
20152404152713 is a deficient number, since it is larger than the sum of its proper divisors (3838035676247).
20152404152713 is a wasteful number, since it uses less digits than its factorization.
20152404152713 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1064917 (or 1064910 counting only the distinct ones).
The product of its (nonzero) digits is 67200, while the sum is 37.
Adding to 20152404152713 its reverse (31725140425102), we get a palindrome (51877544577815).
The spelling of 20152404152713 in words is "twenty trillion, one hundred fifty-two billion, four hundred four million, one hundred fifty-two thousand, seven hundred thirteen".
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