Base | Representation |
---|---|
bin | 11101010100111001111… |
… | …110011010100110110001 |
3 | 21010122212120200120001202 |
4 | 131110321332122212301 |
5 | 231004324423400131 |
6 | 4141453253140545 |
7 | 265413214056101 |
oct | 35247176324661 |
9 | 7118776616052 |
10 | 2015312325041 |
11 | 7077642a5274 |
12 | 2866b802a755 |
13 | 118073a05132 |
14 | 6d782375201 |
15 | 37652437bcb |
hex | 1d539f9a9b1 |
2015312325041 has 16 divisors (see below), whose sum is σ = 2125036166400. Its totient is φ = 1905954977808.
The previous prime is 2015312325007. The next prime is 2015312325053. The reversal of 2015312325041 is 1405232135102.
It is a cyclic number.
It is not a de Polignac number, because 2015312325041 - 234 = 1998132455857 is a prime.
It is a super-2 number, since 2×20153123250412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2015312324995 and 2015312325013.
It is not an unprimeable number, because it can be changed into a prime (2015312325941) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106852670 + ... + 106871528.
It is an arithmetic number, because the mean of its divisors is an integer number (132814760400).
Almost surely, 22015312325041 is an apocalyptic number.
It is an amenable number.
2015312325041 is a deficient number, since it is larger than the sum of its proper divisors (109723841359).
2015312325041 is a wasteful number, since it uses less digits than its factorization.
2015312325041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28268.
The product of its (nonzero) digits is 7200, while the sum is 29.
The spelling of 2015312325041 in words is "two trillion, fifteen billion, three hundred twelve million, three hundred twenty-five thousand, forty-one".
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