Base | Representation |
---|---|
bin | 1001001010100010010110… |
… | …11000000010000101110011 |
3 | 2122100122001201112020201221 |
4 | 10211101023120002011303 |
5 | 10120142324243102201 |
6 | 110510135322005511 |
7 | 4150011231164134 |
oct | 445211330020563 |
9 | 78318051466657 |
10 | 20153251144051 |
11 | 646aa449708a3 |
12 | 2315a03046897 |
13 | b3259c29aa6c |
14 | 4d95cb70bc8b |
15 | 24e3740b74a1 |
hex | 12544b602173 |
20153251144051 has 4 divisors (see below), whose sum is σ = 20582043721632. Its totient is φ = 19724458566472.
The previous prime is 20153251143997. The next prime is 20153251144063. The reversal of 20153251144051 is 15044115235102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20153251144051 - 29 = 20153251143539 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20153251143998 and 20153251144016.
It is not an unprimeable number, because it can be changed into a prime (20153251144151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214396288720 + ... + 214396288813.
It is an arithmetic number, because the mean of its divisors is an integer number (5145510930408).
Almost surely, 220153251144051 is an apocalyptic number.
20153251144051 is a deficient number, since it is larger than the sum of its proper divisors (428792577581).
20153251144051 is an equidigital number, since it uses as much as digits as its factorization.
20153251144051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 428792577580.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 20153251144051 its reverse (15044115235102), we get a palindrome (35197366379153).
The spelling of 20153251144051 in words is "twenty trillion, one hundred fifty-three billion, two hundred fifty-one million, one hundred forty-four thousand, fifty-one".
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