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20154261307 is a prime number
BaseRepresentation
bin10010110001010010…
…011001111100111011
31221000120210112222111
4102301102121330323
5312233442330212
613131515433151
71312304252215
oct226122317473
957016715874
1020154261307
118602611904
123aa57557b7
131b9263930b
14d9299d5b5
157ce58cea7
hex4b1499f3b

20154261307 has 2 divisors, whose sum is σ = 20154261308. Its totient is φ = 20154261306.

The previous prime is 20154261269. The next prime is 20154261319. The reversal of 20154261307 is 70316245102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20154261307 is a prime.

It is not a weakly prime, because it can be changed into another prime (20154261377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077130653 + 10077130654.

It is an arithmetic number, because the mean of its divisors is an integer number (10077130654).

Almost surely, 220154261307 is an apocalyptic number.

20154261307 is a deficient number, since it is larger than the sum of its proper divisors (1).

20154261307 is an equidigital number, since it uses as much as digits as its factorization.

20154261307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 20154261307 in words is "twenty billion, one hundred fifty-four million, two hundred sixty-one thousand, three hundred seven".