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20154300553 is a prime number
BaseRepresentation
bin10010110001010010…
…100011100010001001
31221000120212112211001
4102301102203202021
5312234000104203
613131520335001
71312304504512
oct226122434211
957016775731
1020154300553
118602639342
123aa5774461
131b9265113a
14d929ada09
157ce59991d
hex4b14a3889

20154300553 has 2 divisors, whose sum is σ = 20154300554. Its totient is φ = 20154300552.

The previous prime is 20154300533. The next prime is 20154300583. The reversal of 20154300553 is 35500345102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16730646409 + 3423654144 = 129347^2 + 58512^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20154300553 is a prime.

It is a super-2 number, since 2×201543005532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20154300503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077150276 + 10077150277.

It is an arithmetic number, because the mean of its divisors is an integer number (10077150277).

Almost surely, 220154300553 is an apocalyptic number.

It is an amenable number.

20154300553 is a deficient number, since it is larger than the sum of its proper divisors (1).

20154300553 is an equidigital number, since it uses as much as digits as its factorization.

20154300553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9000, while the sum is 28.

Adding to 20154300553 its reverse (35500345102), we get a palindrome (55654645655).

The spelling of 20154300553 in words is "twenty billion, one hundred fifty-four million, three hundred thousand, five hundred fifty-three".