Base | Representation |
---|---|
bin | 10010110001010010… |
… | …101001010110001001 |
3 | 1221000120220202110211 |
4 | 102301102221112021 |
5 | 312234001334421 |
6 | 13131521041121 |
7 | 1312304634103 |
oct | 226122512611 |
9 | 57016822424 |
10 | 20154324361 |
11 | 8602655216 |
12 | 3aa57861a1 |
13 | 1b9265bc22 |
14 | d929b8573 |
15 | 7ce5a19e1 |
hex | 4b14a9589 |
20154324361 has 2 divisors, whose sum is σ = 20154324362. Its totient is φ = 20154324360.
The previous prime is 20154324349. The next prime is 20154324419. The reversal of 20154324361 is 16342345102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11266548736 + 8887775625 = 106144^2 + 94275^2 .
It is a cyclic number.
It is not a de Polignac number, because 20154324361 - 211 = 20154322313 is a prime.
It is not a weakly prime, because it can be changed into another prime (20154324341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077162180 + 10077162181.
It is an arithmetic number, because the mean of its divisors is an integer number (10077162181).
Almost surely, 220154324361 is an apocalyptic number.
It is an amenable number.
20154324361 is a deficient number, since it is larger than the sum of its proper divisors (1).
20154324361 is an equidigital number, since it uses as much as digits as its factorization.
20154324361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 20154324361 its reverse (16342345102), we get a palindrome (36496669463).
The spelling of 20154324361 in words is "twenty billion, one hundred fifty-four million, three hundred twenty-four thousand, three hundred sixty-one".
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