20154434033 has 4 divisors (see below), whose sum is σ = 20162901108. Its totient is φ = 20145966960.

The previous prime is 20154433991. The next prime is 20154434039. The reversal of 20154434033 is 33043445102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 469502224 + 19684931809 = 21668^2 + 140303^2 .

It is a cyclic number.

It is not a de Polignac number, because 20154434033 - 2¹² = 20154429937 is a prime.

It is a super-2 number, since 2×20154434033² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20154433987 and 20154434005.

It is not an unprimeable number, because it can be changed into a prime (20154434039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4229966 + ... + 4234727.

It is an arithmetic number, because the mean of its divisors is an integer number (5040725277).

Almost surely, 2^20154434033 is an apocalyptic number.

It is an amenable number.

20154434033 is a deficient number, since it is larger than the sum of its proper divisors (8467075).

20154434033 is an equidigital number, since it uses as much as digits as its factorization.

20154434033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8467074.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 20154434033 its reverse (33043445102), we get a palindrome (53197879135).

The spelling of 20154434033 in words is "twenty billion, one hundred fifty-four million, four hundred thirty-four thousand, thirty-three".