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201613440283 is a prime number
BaseRepresentation
bin1011101111000100011…
…0001111010100011011
3201021101210020221110221
42323301012033110123
511300401020042113
6232341523420511
720365111652353
oct2736106172433
9637353227427
10201613440283
117855a592822
12330a7b24737
131602067c678
149a884b3b63
15539ee2a98d
hex2ef118f51b

201613440283 has 2 divisors, whose sum is σ = 201613440284. Its totient is φ = 201613440282.

The previous prime is 201613440239. The next prime is 201613440289. The reversal of 201613440283 is 382044316102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201613440283 is a prime.

It is a super-3 number, since 3×2016134402833 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (201613440289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100806720141 + 100806720142.

It is an arithmetic number, because the mean of its divisors is an integer number (100806720142).

Almost surely, 2201613440283 is an apocalyptic number.

201613440283 is a deficient number, since it is larger than the sum of its proper divisors (1).

201613440283 is an equidigital number, since it uses as much as digits as its factorization.

201613440283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 201613440283 its reverse (382044316102), we get a palindrome (583657756385).

The spelling of 201613440283 in words is "two hundred one billion, six hundred thirteen million, four hundred forty thousand, two hundred eighty-three".